Answer:
54.22 kJ
Explanation:
In this case, we need to calculate the heat. The expression to use is:
Q = m * C * ΔT
Now, with the specific heat of water (4186 J/ kg K), we can calculate the temperature in which this occurs.
So:
Q = 0.550 * 4186 * (105 - T)
Q = 2302.3 (105 - T)
Q = 241,741.5 - 2302.3T
Now with the Aluminium:
Q = 0.855 * 900 * (T - 11)
Q = 769.5T - 8464.5
Now, with both equations, we solve for the final temperature:
769.5T - 8464.5 = 241,741.5 - 2302.3T
(2302.3 + 769.5)T = 241,741.5 + 8464.5
3071.8T = 250,206
T = 81.45 K
This is the temperature which the change occurs. Now, let's determine the amount of heat from water to Al:
Q = 241,741.5 - 2302.3(81.45)
Q = 54,219.17 J or simply 54.22 kJ.
