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2 years ago

Help got 5min left please thank you

Mathematics

1 answer:

Rus_ich [418]2 years ago

5 0

5/6 i think ! because 5 students did out of 6, i could be wrong!

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Which expression is equivalent to 32

Nadusha1986 [10]

2 times (9+7) is correct.

9 + 7 = 16.
16 multiplied by 2 is 32.

3 0

3 years ago

Help me with my math ASAP!!!!

almond37 [142]

Answer:

$f$ = 78

$g$ = 3.5

Step-by-step explanation:

First we need to find $f$ .

We can use the equation $72 + (f + 30) = 180$ to solve for $f$ .

We can then change that equation to $72 + f + 30 = 180$ , since the Commutative Property of Addition says that you can have any addition in any order.

Now, we can solve the equation.

$102 + f = 180\\(102 - 102) + f = 180 - 102\\f = 78$

Now that we solved $f$ , we can now solve for $g$ .

Since 25 equals $8g -3$ , we can solve the equation $8g - 3 = 25$ .

Here is how you solve it:

$8g - 3 = 25\\8g + (-3 + 3) = 25 + 3\\8g = 28\\g = \frac{28}{8}$

Since $\frac{28}{8}$ equals 3.5, which is the simplest form, that is the answer.

Hope this helps, and please mark me brainliest! :)

3 0

2 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$