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2 years ago

The perimter of a rectangle is 90 centimeters.the length is 27 centimeters what is the width of the rectangle

Mathematics

1 answer:

Sati [7]2 years ago

3 0

Answer:

18 cm

Step-by-step explanation:

The perimeter of a rectangle is given by the formula ...

P = 2(L +W)

Fill in the given information and solve for the width.

90 = 2(27 +W)

45 = 27 +W . . . . . divide by 2

18 = W . . . . . . . . . subtract 27

The width of the rectangle is 18 cm.

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NO LINKS!!! What is the transformation f(x)= x^3:

Mama L [17]

Answer:

4. Horizontal shrink by a factor of ¹/₅

5. Left 5, Up 5

6. Right 5, Down 5

Step-by-step explanation:

Transformations of Graphs (functions) is the process by which a function is moved or resized to produce a variation of the original (parent) function.

Transformations

For a > 0

$f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}$

$f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}$

$f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}$

$f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}$

$y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a$

$y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}$

$y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}$

$y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}$

Identify the transformations that take the parent function to the given function.

Question 4

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(5x)^3$

Comparing the parent function with the given function, we can see that the x-value of the parent function has been multiplied by 5.

Therefore, the transformation is:

$y=f(5x) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{5}$

As a > 1, the transformation visually is a compression in the x-direction, so we can also say: Horizontal shrink by a factor of ¹/₅

Question 5

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(x+5)^3+5$

Comparing the parent function with the given function, we can see that there are a series of transformations:

Step 1

5 has been added to the x-value of the parent function.

$f(x+5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units left}$

Step 2

5 has then been added to function.

$f(x+5)+5 \implies f(x+5) \: \textsf{translated}\:5\:\textsf{units up}$

Transformation: Left 5, Up 5

Question 6

$\textsf{Parent function}: \quad f(x)=x^3$

$\textsf{Given function}: \quad f(x)=(x-5)^3-5$

Comparing the parent function with the given function, we can see that there are a series of transformations:

Step 1

5 has been subtracted from the x-value of the parent function.

$f(x-5) \implies f(x) \: \textsf{translated}\:5\:\textsf{units right}$

Step 2

5 has then been subtracted from function.

$f(x-5)-5 \implies f(x-5) \: \textsf{translated}\:5\:\textsf{units down}$

Transformation: Right 5, Down 5

Learn more about graph transformations here:

brainly.com/question/27845947

6 0

1 year ago

Read 2 more answers

The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean

Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51% probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .