<em>Two </em>or <u>more</u> triangles are said to be congruent if and only if they have <u>equal</u> lengths of <em>sides</em> and <u>equal</u> measures of <em>angles</em>.
Thus, the required <u>proof</u> is as shown below:
<u>STATEMENTS </u> <u>REASONS</u>
1. ΔABC and ΔDEC with AB ≅ DE;
BC ≅ EC; <1 ≅ <2 Given
2. <1 and < ABC; < 2 and <DEC are sup <u>Sum</u> of angles on a <em>straight </em>line
3. <ABC ≅ <DEC <em>Congruent</em> angles of <u>similar</u> triangles
4. ∴ΔABC ≅ ΔDEC <em>Side-Angle-Side</em> (SAS) postulate
5. ∴<ACB ≅ <DCE CPCTC postulate
For more clarifications on the properties of congruent triangles, visit: brainly.com/question/1675117
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Answer:
x= 8
Step-by-step explanation:
Step 1- Distribute into the parenthesis by 1.
4x+2+3(-1)+3(-1)x= 7
Step 2- Simplify.
4x+2-3-3x= 7
Step 3- Add common variables.
(4x-3x)+(2-3)
1x-1= 7
Step 4- Add 1 to both sides.
1x-1= 7
+1 +1
1x= 8
Step 5- Divide both sides by 1.
1x= 8
1 1
x= 8
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Answer:
+4
Step-by-step explanation:
-5 - (-9)
-5 + 9
4
The second one!!! For further help use cymath.com
x⁴ + x = 0
x(x³) + x(1) = 0
x(x³ + 1) = 0
x = 0 or x³ + 1 = 0
- 1 - 1
x³ = -1
x = -1
