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Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ =
L.H.S = sin θ cos θ
so, sin θ cos θ ≠ 
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
B, if you want this answer described let me know <span />
Answer:
10
Step-by-step explanation:
A= L²
50 = L² (do opposite operation to find L)
L = 7.07
x²= L²+ L²
x²= 7.07² + 7.07²
x² = 100 ( do opposite operation to make x the subject)
x = 10
Note: opposite operation of square is square root
If 2 equations have the same y-intercept, they are overlapping, which means they have infinite solutions. So there is no way that 2 equations with the same y-intercept will have no solution. Thus your answer is: C)Never.