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Mariana [72]
3 years ago
11

The effects of natural selection are generally seen most quickly in which organisms

Chemistry
1 answer:
Vlada [557]3 years ago
4 0

Bacteria, because the reproduce at fast rates the characteristics of them change and the emergence of antibiotic resistance is what causes the natural selection process to emerge at a high rate.

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Which of the following is a measure of the average kinetic energy of the particles in a sample of matter?
cestrela7 [59]

Answer:

  • <em>Option D. temperature</em>

Explanation:

Indeed it is generally established that <em>temperature is a measure of the kinetic energy ot the particles</em>.

The <em>kinetic energy</em> of a particle is proportional to the product of the mass and the square of the speed. Mathematically, the kinetic energy, KE, is:

  • KE = (1/2) m × v²

Where m is the mass and v the speed of the particle.

In a sample of matter, not all the particles have the same speed, hence not all the particles have the same kinetic energy.

The kinetic energy and the temperature are related by the Boltzman equation:

  • KE = (3/2)KT

Where K is a constant (Boltzman constant) and T is the absolute temperature.

Therefore, as you can see from the last equation, <em>the temperaure is a measure of the averate kinetic energy of the particles in a sample of matter</em>.

This is, at a certain temperature, every substance has the same average kinetic energy.

7 0
3 years ago
In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul
Lady bird [3.3K]

869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have        31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have   X  g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if       188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

about Avogadro’s number

brainly.com/question/1445383

#learnwithBrainly

8 0
4 years ago
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Nicolaas constructed a working model of the hydrologic cycle during science class. He used an open flame, liquid water, two larg
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Surface, condensation, evaporation, precipitation

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Where can you find atoms
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Atoms make up everything, so technically--everywhere.
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Is LiOH soluble or insoluble?
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LiOH is soluble. Na2CO3 is soluble. Cu(OH)2 is insoluble. 
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