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malfutka [58]
3 years ago
10

After 4797 years, how much of the original 250 g of radium-226 remains, if

Chemistry
1 answer:
Setler [38]3 years ago
6 0

Answer:

31.3grams

Explanation:

The amount of a radioactive element that remains, N(t), can be calculated by using the formula;

N(t) = N(o) × 0.5^{t/t(1/2)}

Where;

N(t) = mass of substance remaining

N(o) = mass of original substance

t(1/2) = half-life of substance

t = time elapsed

From the provided information; N(t) = ?, N(o) = 250g, t(1/2) = 1599 years, t = 4797 years

N(t) = 250 × 0.5^{4797/1599}

N(t) = 250 × 0.5^(3)

N(t) = 250 × 0.125

N(t) = 31.25g

N(t) = 31.3grams

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Solution

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Given that you have 14.5 moles of n2, how many moles of h2 are theoretically needed to produce 30.0 moles of nh3 according to re
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45 moles of H₂ are theoretically needed to produce 30.0 moles of NH₃

<h3>Further explanation</h3>

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

  • Mole

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

Mole can also be sought if the amount of substance mass and its molar mass is known

\large{\boxed{\boxed{\bold{mol=\frac{mass}{molar\:mass}}}}

 

Reaction that happens :

N₂ +3H₂ ⇒ 2NH₃

mole N₂ : H₂ : NH₃ = 1 : 3 : 2

To produce 30.0 moles of NH₃,

  • H₂ needed :

mole~H_2~=~\frac{3}{2}\times~30~mole

mole H₂ = 45 mole

  • N₂ needed :

mole~N_2~=~\frac{1}{2}~\times~30

mole N₂ = 15 mole

So the minimum N₂ needed is: 15 mole

14.5 moles of N₂ can only produce NH₃ :

mole~NH_3~=~\frac{2}{1}~\times~14.5

mole NH₃ = 29 mole

<h3>Learn more </h3>

The mass of one mole of raindrops

brainly.com/question/5233234

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moles of water you can produce

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Keywords: mole,  NH₃, N₂, H₂

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