What is the area of this polygon?

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

4 0

Answer:

34.5 units

Step-by-step explanation:

Divide the composite figure into different shapes and then find the areas of all the shapes and add them together to find the total area. We could divide this into 3 triangles and 1 rectangle.

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Let p = x2 + 6.<br> Which equation is equivalent to (22 + 6)2 – 21 = 4x2 + 24 in terms of p?

Alona [7]

Answer:

$\frac{35}{4} =p$

Step-by-step explanation:

p= $x^{2} +6$ ,

(22+6)2-21= $4x^{2} +24$

44+12-21= $4x^{2} +24$

35= $4x^{2} +24$ ,

If you factor out the equation, you get that 35=4p(if you factor it out)

Therefore, $\frac{35}{4} =p$

4 0

3 years ago

Ivan has 4 hours of Music on his MP3 player Jazz makes up 1/6 of the total time how many hours of jazz are on Ivan's MP3 player

Crank

So theres 4 hours and 60min equals 1 hour, so multiply 4 by 60 to get 240, so theres 240 minutes of time on the mp3. So 1/6 of that total time (240min) was on jazz, so what you do is divide 240 by 6 to get 40, so every 1/6 is 40min. So you could say he spend 40min listening to jazz, or you could say he spent 2/3 of an hour listening to jazz

5 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

zheka24 [161]

<h2>Hello!</h2>

The answer is:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$