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Lostsunrise [7]
4 years ago
6

Electricity is distributed from electrical substations to neighborhoods at 1.5×104 V . This is a 60Hz oscillating (AC) voltage.

Neighborhood transformers, seen on utility poles, step this voltage down to the 120V that is delivered to your house.
Part A
How many turns does the primary coil on the transformer have if the secondary coil has 100 turns?
Express your answer using two significant figures. (nprim =?turns)

Part B
No energy is lost in an ideal transformer, so the output power Pout from the secondary coil equals the input power Pin to the primary coil. Suppose a neighborhood transformer delivers 280 A at 120 V. What is the current in the 1.5×104 V line from the substation?
Express your answer using two significant figures.
Physics
1 answer:
ANTONII [103]4 years ago
5 0

Answer:

Np=130 turns, Is=220 A

Explanation:

Part A:

Ns=100 turns

Vp= 1.5*104 V = 156 V

Vs= 120 V

As Np/Ns= Vp/Vs

⇒ Np= \frac{Vp}{Vs}*Ns

⇒Np=\frac{156*100}{120}

Np= 130 turns (It has two significant figures)

Part B

Is=280 A, Vs=120 V, Vp= 1.5*104 V= 156 V

For ideal transformer

Pin=Pout

Ip*Vp= Is*Vs

⇒Ip=(\frac{Is*Vs}{Vp})

⇒Ip=\frac{280*120}{156}

⇒Ip=215.4 A

to represent it as two significant figures we will write as

⇒Ip=220 A

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