Answer:
(a) E=λ/(2\pi e0 r)
(b) E = 0
Explanation:
(a) We can use the Gaussian's Law to calculate the electric field at any distance r from the axis. By using a cylindrical Gaussian surface we have:
![\int \vec{E}\cdot d\vec{r}=\frac{\lambda}{\epsilon_o}](https://tex.z-dn.net/?f=%5Cint%20%5Cvec%7BE%7D%5Ccdot%20d%5Cvec%7Br%7D%3D%5Cfrac%7B%5Clambda%7D%7B%5Cepsilon_o%7D)
where λ is the total charge per unit length inside the Gaussian surface. In this case we have that the Electric field vector is perpendicular to the r vector. Hence:
![E\int dr=E2\pi r=\frac{\lambda}{\epsilon_o}\\\\E=\frac{\lambda}{2\pi r \epsilon_o}](https://tex.z-dn.net/?f=E%5Cint%20dr%3DE2%5Cpi%20r%3D%5Cfrac%7B%5Clambda%7D%7B%5Cepsilon_o%7D%5C%5C%5C%5CE%3D%5Cfrac%7B%5Clambda%7D%7B2%5Cpi%20r%20%5Cepsilon_o%7D)
(b) outside of the outer cylinder there is no net charge inside the Gaussian surface, because charge of the inner radius cancel out with the inner surface of the cylindrical conductor.
Hence, we have that E is zero.
hope this helps!!
Answer :the resultant of two vectors can be found using either the parallelogram method or the triangle method. don't know if this was helpful ?
Explanation:
Answer:
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No. All rock types can be used, many principles also apply to igneous rock
Answer:
dd activated carbon media to the filter
Explanation:
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