Question

If a = 2.0 cm, b = 5.0 cm, and i = 20 a, what is the magnitude of the magnetic field at the point p?

Answer 1

If a = 2.0 cm, b = 5.0 cm, and i = 20 a,  6.0 μt is the magnitude of the magnetic field at the point p, So the correct option is (a).

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

$B_{1}$ = μ$_{0}$ i $\frac{\pi }{6}$ / $4\pi (a+b)$

$B_{2}$ = μ$_{0}$ i $\frac{\pi }{6}$ / $4\pi b$

As, $B_{1}$ is moving down and $B_{2}$ is moving up so,

$B_{2}$ - $B_{1}$ = (μ$_{0}$ i $\frac{\pi }{6}$ / $4\pi b$) -  [μ$_{0}$ i $\frac{\pi }{6}$ / $4\pi (a+b)$]

$B_{2}$ - $B_{1}$ = μ$_{0}$ i 24 / $(\frac{1}{b} - \frac{1}{a+b} )$

$B_{2}$ - $B_{1}$ = $\frac{4\pi *10^{-7}*20 }{24} (\frac{1}{0.05} -\frac{1}{0.02})$

$B_{2}$ - $B_{1}$ = 5.98×$10^{-6}$ T ≈ 6μT

Therefore,  6.0 μt is the magnitude of the magnetic field .

Learn more about  magnetic field here;

brainly.com/question/23096032

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