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Cloud [144]
3 years ago
15

You are given an unknown solid substance of mass 500 g and you want to estimate its specific heat. unfortunately, you don’t have

a thermometer handy. instead, you throw the substance into a bucket of boiling water and wait until its in equilibrium with the boiling water. you then remove the hot substance from the boiling water and put it into a beaker with 400 ml ethyl alcohol at room temperature. immediately after adding the hot substance into the beaker, the volume scale reads 430 ml. after a while, when the alcohol and the substance reach equilibrium, the volume scale reads 429 ml.
What is the specific heat of the substance?
Hint: Assume that no heat was neither lost during the transfer nor to the environment. You can neglect the mass of the beaker. Room temperature is approximately 20 deg C and the density of ethyl alcohol is 789 kg/m^3.

A) 385 J/(mol K)
B) 4,057 J/mol K)
C) 2,090 J/(mol K)
D) 449 J/(mol K)
E) 7,500 J/(mol K)
Physics
1 answer:
Julli [10]3 years ago
7 0

Answer:

Option C) 2,090 J/(mol K)

Explanation:

Data:

Volume in the beaker = 429 ml

temperature  = 20° C

Density = 789 kg/m³

Equilibrium reading = 429

volume change = 29 ml

                          = 0.029 L

Energy change = mcΔT

                       U + PΔV

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kipiarov [429]

Answer:

1.04 s

Explanation:

The computation is shown below:

As we know that

t = t' × 1 ÷ (√(1 - (v/c)^2)

here

v = 0.5c

t = 1.20 -s

So,

1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)

1.20 = t' × 1 ÷ (√(1 - (0.5)^2)

1.20 = t' ÷ √0.75

1.20 = t' ÷ 0.866

t' = 0.866 × 1.20

= 1.04 s

The above formula should be applied

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3 years ago
Someone please help ! this is worth 40 points!!
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A 60 kg sprinter has a momentum of +600 kg-m/s when he crosses the finish
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Answer:

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In terms of an equation,

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