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3 years ago

12

4/5 times 3/4 and 5/7 9/10

1 answer:

VikaD [51]3 years ago

5 0

Answer:

(20) ( 12) (35), (90)= 756,000

Step-by-step explanation: because you multiply all of them which gives you 756,000.

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What are the zeros of f(x) = x2 + 3x – 10?

Nady [450]

Step One
Factor f(x)
f(x) = (x + 5)(x - 2)

Step Two
The zeros occur when either (x + 5) = 0 or (x - 2) = 0

x + 5 = 0
x = -5

x - 2 =0
x = 2

Step 3
Record the zeros
(-5,0) or (2,0) <<<<<< answer.

3 0

2 years ago

Help me out please please an thank you

Katena32 [7]

Answer:

29

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me !! pls pls pls

frutty [35]

Answer:

aas congruence postulate

6 0

2 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Please help me with this question.

mixas84 [53]

Answer:

B

Step-by-step explanation:

In a triangle, the sum of any two sides must be bigger than the third.

For the first one, 10+20=30 is not greater than 30, so this is not correct.

For B, 122+137 = 259 > 257, 257+137>122 , and 257 + 122 > 137. This works

For C, 8.6 + 2.7 = 11.3 < 12.2, so this does not work

For D, 1/6 + 1/5 = 5/(6*5) + 6/(6*5) = 5/30 + 6/30 = 11/30 < 1/2 = 15/30, so this does not work

7 0

3 years ago