Answer:
y = 33.75 m/s.
Step-by-step explanation:
The graph of the rocket's velocity with respect to time looks as follows :
...(1)
Where x is time in seconds
We need to find the velocity of rocket after 15 seconds. Put x = 15 in equation (1).
![y=0.15\times (15)^2\\\\=33.75\ m/s](https://tex.z-dn.net/?f=y%3D0.15%5Ctimes%20%2815%29%5E2%5C%5C%5C%5C%3D33.75%5C%20m%2Fs)
Hence, the speed of the rocket after 15 seconds is 33.75 m/s.
Answer:
y+3= -4x
Step-by-step explanation:
general equation is (y-y1) = m(x-x1)
m=rise/run= -4/1 (is negative because looking from left to right on the graph it goes downward)
pick any point on the line to put in. the equation for example (0,-3)
y+3= -4x
Answer: lower bound = 0.7404; upper bound = 0.8596
Step-by-step explanation:
The proportion p for this population:
p = ![\frac{240}{300}](https://tex.z-dn.net/?f=%5Cfrac%7B240%7D%7B300%7D)
p = 0.8
Confidence interval for proportion is calculated as:
p ± z-score.![\sqrt{\frac{p(1-p)}{n} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%7D)
Z-score for a 99% confidence interval is: z = 2.58
Calculating:
0.8 ± 2.58.![\sqrt{\frac{0.8(0.2)}{300} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B0.8%280.2%29%7D%7B300%7D%20%7D)
0.8 ± 2.58.![\sqrt{0.00053}](https://tex.z-dn.net/?f=%5Csqrt%7B0.00053%7D)
0.8 ± 2.58(0.0231)
0.8 ± 0.0596
This means that the lower limit of this interval is 0.7404 and upper bound is 0.8596
The z-score for men at 64 inches is:
![z=\frac{64-69.3}{2.84}=-1.866](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B64-69.3%7D%7B2.84%7D%3D-1.866)
Using a standard normal distribution table, we can see that the cumulative probability for a z-score of -1.866 is 0.031.
The answer is 3.1%.
Answer:
2.8 in
Step-by-step explanation:
The volume of any shape is given as the product of base area and height. Therefore, V=Ah
Where A is cross sectional area, h is height
For a triangular, the cross sectional area is given by ½lw where l is length and w is width.
Now v=½lwh
Given that v=4 in³
4=½lwh
8=lwh
Considering the given choices, l can be 2.8 in