Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The power created is
Explanation:
From the question we are told that
The that the average power is mathematically represented as
Where W is is the Workdone which is mathematically represented as
Where F is the applies force and s is the displacement due to the force
So
Now this displacement can be represented mathematically as
Where is the average velocity and is the time taken
So
=>
Answer:
Height as seen by the professor = 38.2 m
Explanation:
Angle of throw = θ = 69°
Velocity of throw = v
X component of velocity = v₁ = v cos 69 = 0.3584 v m/s
Vertical component of the velocity = v₂ = v sin 69 = 0.9336 v m/s
v₂ / v₁ = tan 69 = 2.605
v₂ = 2.605 v₁.
Professor sees as if the x component of velocity =0
v (as seen by professor) + v' = 0
=> v as seen by professor = -v' = -10.5 m/s
This shows that y component of the ball's velocity is 2.605 times its x component of velocity.
with respect to the professor, there is only y component of velocity.
v₂' =v₂ = 2.605 ( -10.5) = 27.4 m/s.
Height as seen by the professor = (27.4)² / 2(9.8) = 38.2 m
Answer:
I'm not sure if I have the right words for it, but it is most likely that all three rays will form a larger inverted image after they pass through the lens because the arrow is outside the focal point. The image will be outside of F2, like the arrow is outside of F1.
Explanation:
Due to the shape of the lens in the diagram, you can imagine 3 lines branching out from point Q. I've made a digital sketch about what will happen as they pass through. It's a little crude, but it still works. I hope this was helpful.