Please help me with the correct answer

A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction

steposvetlana [31]

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

vavg = average velocity.

Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

vavg = s/t

Have a nice day!

6 0

3 years ago

On a day when the temperature reaches 50°F, the temperature in degrees Celsius is: 20°C

anzhelika [568]

Answer:

10°C

Explanation:

To convert °F to °C, we use the formula:

°C = (°F - 32) * ( 5/9)

So, to convert 50°F to the equivalent in °C, we can proceed as follows:

°C = ( 50 - 32 ) * (5/9)

°C = ( 18 ) * (5/9), which is, approximately,

°C = 9.999999999... ≈ 10 (5/9 ≈0.555555...)

So, 50°F is equivalent to 10°C.

3 0

3 years ago

Pure water is a(n) _____.

Mashutka [201]

The correct answer would be compound

6 0

3 years ago

Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m

Ket [755]

Answer:

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

Explanation:

Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

$V_{escape}=\sqrt{\frac{2GM}{R}}$

$V_{escape}=$ Escape velocity

G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²

M= mass of Mars = 6.42×10²³ kg

R = Radius of the Mars = 3.40×10³m

The escape velocity does not depend on the velocity of a object.

$V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}$

$=15.88 \times 10^4$ m/s

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

3 0

3 years ago

What is the force on a body if the mass of the body is 2300g? (acceleration due to = 9.8ms-1)

amm1812

Hello jamaicandoll!

$\huge \boxed{\mathfrak{Question} \downarrow}$

What is the force on a body if the mass of the body is 2300g? (acceleration due to gravity = - 9.8m/s²) .

$\huge \boxed{\mathfrak{Answer} \downarrow}$

Given,

Mass (m) = 2300 g = 2.3 kg
Acceleration (a) = -9.8 m/s²
Force (F) = ?

We know that, force = mass × acceleration.

So,

F = ma

F = 2.3 × -9.8

F = $\boxed{\underline{\bf \: -22.54\:N}}$

__________________

Hope it'll help you!

ℓu¢αzz ッ

5 0

2 years ago

Please help me with the correct answer​

Please help me with the correct answer