Answer:
<h3>14.97m/s</h3>
Explanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
Formulas change from F to degree C : C = ( F - 32 )/1.8
so we have (77-32)/1.8 = 25 oC
ok done. Thank to me :>
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The other questions involve words or phrases with ambiguous definitions,
that can mean different things to different people, and would be hard to
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First we need to convert the angular speed from rpm to rad/s. Keeping in mind that


the angular speed is

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion: