We want to see how many solutions has an equation given some restrictions on the vectors of the equation.
We have 3 vectors in R2.
v₁, v₂, and v₃.
Where we know that v₁ and v₂ are parallel. And two vectors are parallel if one is a scalar times the other.
Then we can write:
v₂ = c*v₁
Where c is a real number.
Then our system:
x*v₁ + y*v₂ = v₃
Can be rewriten to:
x*v₁ + y*c*v₁ = v₃
(x + y*c)*v₁ = v₃
Assuming x, y, and c are real numbers, this only has a solution if v₁ is also parallel to v₃, because as you can see, the equation says that v₃ is a scallar times v₁.
Geometrically, this means that if we sum two parallel vectors, we will get a vector that is parallel to the two that we added.
If you want to learn more, you can read:
brainly.com/question/13322477
Answer:
T = 88 degrees to the nearest degree
Step-by-step explanation:
To find the measure of the angle T, we can use the cosine rule
We have the formula as;
t^2 = u^2 + v^2 - 2uv Cos T
t = 8.1
u = 7.1
v = 4.2
8.1^2 = 7.1^2 + 4.2^2 - 2(7.1)(4.2) cos T
-2.44 = -59.64 cos T
cos T = (2.44)/(59.64)
T = arc cos (2.44/59.64)
T = 87.66
to the nearest degree, this is 88 degrees
So bigest to smallest? 1/2, 1/5, 1/6.
If the other way, just flip it around.
Answer:
B
Step-by-step explanation:
2x = 6+14
2x = 20
x = 10
To convert the angle in radian measure to degree measure, multiply it by 180/π.
The given angle in radian measure is 257π/360 . Multiply it by 180/π to get the angle in degrees.
So,
The angle in degrees = 257π/360 x 180/π = 257/2 = 128.5 degrees