X^2-12x+7=0 move constant to other side
x^2-12x=-7 add the square of half the linear coefficient to both sides...(12/2)^2=36
x^2-12x+36=29 now the left side is a perfect square...
(x-6)^2=29 so if
f(x)=(x-a)^2+b then
f(x)=(x-6)^2-29
So a=6
Answer:
its 25
Step-by-step explanation:
if you divide 125 and 5 you get 25
then if you divide 170 and you get 21.25 but you want to round it to 25
hope this helps plz let me have brainliest
23.83 your welcome goooooooood
The answer is no solution
