Answer:
d≈ 1.15 g/cm^3
Explanation:
The density of an object can be found by dividing the mass over the volume.
d= m/v
The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.
m= 54.3 g
v= 47.18 cm^3
Substitute the values into the formula.
d= 54.3 g/ 47.18 cm
Divide.
d= 1.150911403136922 g/cm^3
Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.
d ≈ 1.15 g/cm^3
The density is about 1.15 grams per cubic centimeter.
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<span>The most common form of matter on the universe is Plasma. Plasma allows ions and electrons to coexist, which, funny thing, </span><span>plasmas are the most common state of matter in the universe.</span>
Molar mass:
KOH = 56.0 g/mol
Number of moles of KOH :
5.93 / 36.5 => 0.1624 moles
<span>KOH + HCl = KCl + H₂O
</span>
1 mole KOH --------------> 1 mole HCl
0.1624 moles KOH ----> ?
moles HCl = 0.1624 x 1 / 1
= 0.1624 moles of HCl
V ( HCl ) = moles / molarity
V(HCl) = 0.1624 / 0.183
V (HCl) = 0.887 L x 1000 = 887 mL
hope this helps!
<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are 
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of ethinyl estradiol = 0.038 mg = 
(Conversion factor: 1 g = 1000 mg)
Molar mass of ethinyl estradiol ![(C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol](https://tex.z-dn.net/?f=%28C_%7B20%7DH_%7B24%7DO_2%29%3D%5B%2820%5Ctimes%2012%29%2B%2824%5Ctimes%201%29%2B%282%5Ctimes%2016%29%5D%3D296g%2Fmol)
Putting values in above equation, we get:
According to mole concept:
1 mole of a compound contains 
number of molecules
So, 
of ethinyl estradiol will contain = 
number of molecules
Hence, the number of molecules of ethinyl estradiol present in one pill are
