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anygoal [31]
3 years ago
14

The specific heat of ice is 0.5 calories/gram.

Chemistry
1 answer:
dsp733 years ago
4 0

Answer:

Q = 30 calories

Explanation:

We have,

The specific heat of ice is 0.5 calories/gram.

The heat require to raise the temperature is given by :

Q=mc\Delta T

m = 60 grams, c = 0.5 calories/gram °C, \Delta T=1\ C

So,

Q=60\times 0.5\times 1\\\\Q=30\ \text{calories}

So, 30 calories of heat is required to raise the temperature by 1 C.

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