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anygoal [31]
3 years ago
14

The specific heat of ice is 0.5 calories/gram.

Chemistry
1 answer:
dsp733 years ago
4 0

Answer:

Q = 30 calories

Explanation:

We have,

The specific heat of ice is 0.5 calories/gram.

The heat require to raise the temperature is given by :

Q=mc\Delta T

m = 60 grams, c = 0.5 calories/gram °C, \Delta T=1\ C

So,

Q=60\times 0.5\times 1\\\\Q=30\ \text{calories}

So, 30 calories of heat is required to raise the temperature by 1 C.

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Help please I put what I thought thank you so much
Alik [6]

Answer:

your answer second once is correct

Explanation:

don't worry! have a good day dear!!..

6 0
3 years ago
A gas at constant volume has a pressure of 4. 50 atm at 200. K. What will be the pressure of the gas at 250. K? 3. 60 atm 4. 60
Trava [24]

5.625 atm will be the pressure of the gas at 250 K temperature of the gas at constant volume.

<h3>How we calculate the pressure of the gas?</h3>

Pressure of the gas will be calculated by using the ideal gas equation as:

PV = nRT,

From the question, it is clear that:

Moles of the gas and volume is constant here, so we calculate the pressure by rearranging the above equation as:

P/T = nR/V

And required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = pressure of gas = 4.50 atm

T₁ = temperature of gas = 200 K

P₂ = pressure of gas = to find?

T₂ = temperature of gas = 250 K

On putting all these values in the above equation, we get

P₂ = 4.50 × 250 / 200 = 5.625 atm

Hence, 5.625 atm is the pressure of the gas.

To know more about ideal gas equation, visit the below link:

brainly.com/question/1056445

5 0
3 years ago
Water is produced from the reaction of hydrogen and oxygen gas, according to the equation below. What is the excess reactant in
liq [111]

Explanation:

Mole ratio of Oxygen to Hydrogen gas = 1 : 2.

If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.

However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)

3 0
3 years ago
A sample of 2.45g aluminum oxide decomposes into 1.3g of aluminum and 1.15g of oxygen. What is the percentage composition of the
Vitek1552 [10]

Answer:

%Al = 53.1%%

%O = 46.9%

Explanation:

If we know the grams of a chemical compound in a specific reaction, it is possible to know the percentage of each atom that composes it.

For the Aluminum Oxide in this problem, we know its total weight and the grams of each component.

therefore we can determine the percentage ratio of its components through:

For Al

%Al = \frac{mass of Al}{mass of Aluminium oxide} . 100%

% Al = \frac{1,3 g}{2,45 g} . 100%

%Al = 53.1%%

In the same way for oxygen

%O = \frac{mass of O}{mass of Aluminium oxide} . 100%

%O = \frac{1,5 g}{2,45 g} . 100%

%O = 46.9%

5 0
3 years ago
What type of reaction is illustrated below?2H1 --&gt; H2 + 12
Artyom0805 [142]

Answer:

Decomposition reaction.

Explanation:

2HI —> H₂ + I₂

From the above equation, we can see clearly that HI undergoes a reaction to produce H₂ and I₂ which are the elements that make up HI.

Therefore, the equation illustrated above is a decomposition reaction because HI breaks into H₂ and I₂

NOTE: Decomposition reaction is a reaction in which a compound splits or breakdown into two or more simple elements or compound.

7 0
3 years ago
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