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timurjin [86]
2 years ago
11

Natasha is a bank teller. She received a 5% raise last year and a subsequent merit raise of 3% this year. What is the accumulati

ve or compound effect of these two raises as a percentage? Use the 1+ track of the last nine lines of Section 3.5 of the text and do not round.
(a) 8% (b) 15% (c) 8.15% (d) 0.15% (e) 2% (f) none of the above
Mathematics
1 answer:
Anvisha [2.4K]2 years ago
8 0

Answer:

The correct answer is C. 8.15%.

Step-by-step explanation:

Given that Natasha is a bank teller, and she received a 5% raise last year and a subsequent merit raise of 3% this year, to determine what is the accumulative or compound effect of these two raises as a percentage, the following calculation must be performed, assuming, as an example, that her starting salary was $ 2,000:

(2,000 x 1.05) x 1.03 = X

2,100 x 1.03 = X

2,163 = X

2,000 = 100

2,163 = X

2,163 x 100 / 2,000 = X

216,300 / 2,000 = X

108.15 = X

108.15 - 100 = 8.15

Thus, the compound effect of both salary increases is a salary increase of 8.15%.

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What is the perpendicular slope to 6/-3
IRISSAK [1]

Answer:

Perpendicular slope is \frac{3}{6} or \frac{1}{2}.

Step-by-step explanation:

Given:

Let the perpendicular slope be x.

The given slope is \frac{6}{-3}

For perpendicular slopes, the product of the slopes is equal to -1.

Therefore, x\times \frac{6}{-3}=-1\\-\frac{6}{3}x=-1\\6x=3\\x=\frac{3}{6}=\frac{1}{2}

Therefore, the perpendicular slope is \frac{3}{6} or \frac{1}{2}.

8 0
3 years ago
Which expression is equivalent to i 233?<br> a)1<br> b)–1<br> c)i<br> d)–i
Aneli [31]

We have to find the value of the expression i^{233}

We know that the below values.

i^2=-1\\i^4=1

Hence, in order to find the value of the given expression, we can first rewrite it in terms of i^4

i^{233}=(i^4)^{58}\cdot i

Now, we know that i^4=1

Hence, we have

i^{233}=(1)^{58}\cdot i

i^{233}=1\cdot i

i^{233}=i

C is the correct option.

5 0
3 years ago
Read 2 more answers
Linear equation for (-5,3) and (-1,-1)
Alex787 [66]

Answer:

y = -x - 2

Step-by-step explanation:

y = mx + c

m = (-1-3)/(-1-(-5)) = -4/4 = -1

y = -x + c

(-1,-1)

-1 = -(-1) + c

c = -2

y = -x - 2

6 0
3 years ago
the pictograph below shows number of packages of different brand of batteries at a store sold on Fridaywhich statement is best s
Wewaii [24]
I am happy to help... but <span>Please be more specific with your question. </span>
8 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
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