Answer:
Perpendicular slope is
or
.
Step-by-step explanation:
Given:
Let the perpendicular slope be x.
The given slope is 
For perpendicular slopes, the product of the slopes is equal to -1.
Therefore, 
Therefore, the perpendicular slope is
or
.
We have to find the value of the expression 
We know that the below values.

Hence, in order to find the value of the given expression, we can first rewrite it in terms of 

Now, we know that 
Hence, we have



C is the correct option.
Answer:
y = -x - 2
Step-by-step explanation:
y = mx + c
m = (-1-3)/(-1-(-5)) = -4/4 = -1
y = -x + c
(-1,-1)
-1 = -(-1) + c
c = -2
y = -x - 2
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Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:

and now the derivative of this expression with respect to "t" is:

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then

is continuous on [a,b], differentiable on (a,b) and 
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:
