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Paraphin [41]
3 years ago
9

What is the slope of a trend line that passes through the points (1, 3) and (10, 25)?

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0
-15/2 you go up then down
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{[20/(8+2)]^6+6}/(4^2/2)
Naddika [18.5K]
So for this problem we need to do order of operations so the very first step that we need to do here is (8+2) because that is the smallest enclosed symbols (8+2)=10 next divide by 20 because that is the next step in the equation which 20/10=2, so now we have {[2]^6+6} and due to order of operations the next step here is to take 2 to the power of 6 which is 64 so now we have {64+6} which is 70 so now we have 70/(4^2/2) and due to order of operations we do the parentheses first and that would mean that we do 4^2 because exponents come after parantheses like so,
70/(16/2) now we do 16/2 because its still inside the paranthesess so 16/2=8 so now we have 70/8 and that equals are end answer of 8.75 Enjoy!=)
7 0
3 years ago
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Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
The numbers 22 and 35 are relatively prime. TrueFalse
aliina [53]

Answer: True

Step-by-step explanation:

8 0
3 years ago
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What is the perimeter of this triangle? 15 cm 5 cm 25 cm 10 cm
Lady_Fox [76]

Answer:

55

Step-by-step explanation:

Add 15+5+25+10 which is 55

hope this helps! :)

3 0
3 years ago
Lines j, k, m, and n lie in a plane. You know line j is perpendicular to line n, m is perpendicular to line n, and line k is par
Alex_Xolod [135]
B it is no problem I don't think it's that answer but yea
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3 years ago
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