HELP!! Given f(x)=5x squared and g(x) = x squared + 2x squared - 5x, what is F (x) * g(x)?

1 answer:

8 0

X^2+2x^2-5x

((x^2)+2x^2)-5x

Pull the factors out

3x^2-5x=x(3x-5)

x(3x-5)

x(3x-5)*5x^2

5x(3x-5)*x^2

Final

5x^3*(3x-5)

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PART A

The given equation is

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In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

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We add and subtract

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$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

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The quadratic trinomial above is a perfect square.

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PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

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This implies that,

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$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

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