Find the area of a regular hexagon with side length of 10 and apothem of 8.7 meters HELP PLZZZ
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By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:
, where 
represents the points being passed through.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:
From the given data sets we shall obtain the answers as follows:
<span>301 345 305 394 328 317 361 325 310 362
Re-arrange the data in ascending order:
301, 305, 310, 317,325, 328, 345, 361, 362, 394
from the above we see that:
Minimum value=301
Q1=310
median=(325+328)/2=326.5
Q3=361
Maximum value=394
Thus the box plot will be as follows:
</span>
<span>301 345 305 394 328 317 361 325 310 362
Re-arrange the data in ascending order:
301, 305, 310, 317,325, 328, 345, 361, 362, 394
from the above we see that:
Minimum value=301
Q1=310
median=(325+328)/2=326.5
Q3=361
Maximum value=394
Thus the box plot will be as follows:
</span>