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agasfer [191]
3 years ago
14

(4.5 x 104) + (300) =

Mathematics
2 answers:
artcher [175]3 years ago
7 0

Answer:

768

Step-by-step explanation:

telo118 [61]3 years ago
5 0
(768) 4.5•104= 468 and add by 300 it is (768)
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Can someone help plz?????
Keith_Richards [23]

Answer:

B

Step-by-step explanation:

-2-(-4) = -2 + 4

B shows subtracting 2 to the left then adding 4 to the right.

6 0
3 years ago
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Mathew decides to run his first 50K (km) Ultra-Marathon. If 0.62 miles = 1 km, how many miles is Mathew going to run? * (please
kirza4 [7]

Answer:

31 miles

Step-by-step explanation:

If you multiply 0.62 by 50 you will get 31.

Please keep in mind that I am human and make mistakes. This answer could be wrong but this is my opinion on what the answer is.

4 0
3 years ago
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I'm not sure what they mean by "relations that represents a function". I don't understand this.
sergeinik [125]
Means, for every 1 input, there is 1 coresponding output
normally x is input and y is output in form (x,y)
so just look for the option(s) that has/have every first number repeat with only 1 2nd number

A. -7 repeats with 5 and -3, not a function

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C. no repeats, function

D. no repeats, function


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4 0
3 years ago
You are designing an aquarium that is to have a tank holding 225,000 gallons of water. The tank will be 100 feet long and 20 fee
vladimir2022 [97]
Well I'm just doing some random math so it might be 300?
5 0
3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
4 years ago
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