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Aleks04 [339]
3 years ago
14

I need help with this.​

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer:

x + (3x - 9) = 5x - 30 \\ x + 3x - 9 = 5x - 30 \\ 4x - 9 = 5 x - 30 \\  - 9 + 30 = 5x - 4x \\ 21 = x \\ so..value \: of \: x \: is \: 21 \\ so. \\

<ACB = 105°

<h2>it is correct✅ ans. </h2>

❤❤❤❤❤❤❤❤❤

<h3>plazzz mark is as a brilliant ans</h3>
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A flat rectangular piece of aluminum has a perimeter of 70 inches. The length is 11 inches longer than the width. Find the width
rodikova [14]

perimeter = 2L +2w

L = w+11

70 = 2(w+11) +2w

70 = 2w+22+2w

70= 4w + 22

48 = 4w

w=48/4 = 12

width = 12

length = 12+11 = 23

2x12 = 24

2x23 = 46

46+24 = 40

 length = 23 inches, width = 12 inches

Answer is D

5 0
3 years ago
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Help please!! It would be nice if you could add an explanation, but you don't have to. I just need the answer.
Firlakuza [10]
The answer is B I solved this my self
4 0
2 years ago
Pls help - Left 1 day
aalyn [17]

Answer:

31

Step-by-step explanation:

it said 22 2's , so 22 + 9

and 0,1,3,4,5,6,7,8,9 is 9 numbers

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2 years ago
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In which of these situations do the quantities combine to make 0?
leva [86]

Answer:

b is the correct answer

4 0
3 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
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