The correct option for The firm enjoys economies of scope.
economies of scope exist if C(Q1, 0) + C(0, Q2) > C (Q1, Q2) (10 + 5Q1) + (10 + 5Q2) > 10 + 5Q1 + 5Q2 - 0.2Q12Q2.
Economies of scope is an economic theory stating that the average total cost of production decrease as a result of increasing the number of different goods produced. For example, a gas station that sells gasoline can sell soda, milk, baked goods, etc.
Economies of scope is a financial precept wherein a commercial enterprise's unit value to supply a product will decline because the form of its products will increase. In different words, the extra one of kind-but-comparable goods you produce, the lower the total cost to provide each one may be.
Your question is incomplete. Please read below for the missing content.
A firm can produce two products with the cost function C(Q1, Q2) = 10 + 5Q1 + 5Q2 - 0.2Q1Q2. The firm enjoys:
A. economies of scale in the two products separately.
B. economies of scope.
C. cost complementarity.
D. economies of scale in the two products separately and cost complementarity.
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The San Francisco Giants sell tickets based on <u>dynamic pricing</u>, <span>where the prices often change based on demand and other variables.
This means that these tickets are based on how much a regular customer is willing to pay. There is an approximate price that seems reasonable for customers, and it can fluctuate, but still it is the best way to buy or sell something and profit after it. </span>
Answer:
Depends on the person but probably not
Explanation:
The implied quality weight is 6/10 = 0.6. A year lived with chpitis scars is only 60% as satisfying as living a year in full health.
Answer:
$950 in order to maximize the revenue.
Explanation:
The computation of monthly rent in order to maximize revenue is shown below:-
R (x) = Rent price per unit × Number of units rented
= ($900 + $10 x) × (100 - x)
= $90,000 - 900 x + 1000 x - 10 x^2
R (x) = -10 x^2 + 100 x + $90,000
Here to maximize R (x), we will find derivative and equal it to zero
R1 (x) = -20 x + 100 = 0
20 x = 100
x = 5
Therefore the monthly rent is p(5) = $900 + 10(5)
= $900 + 50
= $950 in order to maximize the revenue.
