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vesna_86 [32]
3 years ago
8

Which waves can travel through a vacuum? A) light waves Eliminate B) ocean waves C) sound waves D) mechanical waves

Physics
2 answers:
wariber [46]3 years ago
6 0

The answer is A! I hope this helps!

Artemon [7]3 years ago
3 0

Electromagnetic waves are the waves which can also travel through the vacuum. Example of electromagnetic waves are - Radio waves , micro waves, Infrared waves, Light (visible portion of electromagnetic spectrum), Ultraviolet rays, Xrays and gamma rays.

Hence A that is light waves is the correct option.  

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Un adolescente que va en monopatín rueda hacia abajo sobre un plano inclinado de 18.0 m de largo. El chico parte con una rapidez
qaws [65]

Answer: 31.62°

Explanation:

Tenemos como datos:

Distancia = 18.0m

Velocidad inicial = 2.0 m/s

Tiempo total = 3.3s

Sabemos que para un plano inclinado (ignorando el rozamiento) la aceleración se escribe como:

a(t) = g*sen(θ)

donde θ es el ángulo del plano inclinado, y g = 9.8m/s^2

Sabemos que para la velocidad tenemos que integrar la aceleración sobre el tiempo, entonces:

v(t) = g*sen(θ)*t + v0

Donde v0 es la velocidad inicial: v0 = 2.0m/s

v(t) = 9.8m/s^2*sen(θ)*t + 2.0m/s

Y para la posición, podemos integrar de vuelta sobre el tiempo:

p(t) = 0.5*9.8m/s^2*sen(θ)*t^2 + 2.0m/s*t + p0

Donde p0 es la posición inicial, podemos considerar que es cero para este problema.

p(t) = 4.9m/s^2*sen(θ)*t^2 + 2.0m/s*t

Y usando los datos iniciales, sabemos que en 3.3 segundos se recorren 18 metros, entonces:

p(3.3s) = 18m = 4.9m/s^2*sen(θ)*(3.3s)^2 + 2.0m/s*3.3s

              18m = 51.744m*sen(θ) + 6.6m

              sen(θ) = (18m - 6.6m)/ 51.744m

                   θ = cosec( (18m - 6.6m)/ 51.744m ) = 31.62°

4 0
3 years ago
A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
Alexus [3.1K]
At 10 m/s, it will take
  (2 m)/(10 m/s) = 0.2 s
to bridge the gap.

_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.

3 0
3 years ago
Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane?
Sindrei [870]
Normal force=m*g*cos theta
normal force=92kg*9.8m/s^2*cos 42
normal force=670 N
7 0
3 years ago
Read 2 more answers
compare the different ways a musician changes the pitch while playing a stringed instrument or playing a wind instrument
alexdok [17]
(This is from experience so sorry if it's wrong but) When wind instruments are played, sometimes the notes go flat or sharp depending on the speed the player blows air into the instrument as well as the warmth of the air. When playing a string instrument, the pitch can be changed in many ways. For example, when the player places their fingers on the string depending on which part of the tip of the finger you use, the tone of the sound and sometimes the pitch, changes. Looking at the question in a different way, you can change the pitch and the range of notes you can reach on the instrument (both wind and string) by changing the note you tune your instrument to. Hope this helps!!
3 0
4 years ago
Calculate the hang time of a person who moves 3 m horizontally during a 1.25-m high jump. What is the hang time when the person
jekas [21]

The duration of time for which an object stays in air is called the hang time.

For an athlete who moves 3m horizontally during a 1.25m high jump, the hang time will be the sum of the time taken by the athlete to reach the maximum height and the time taken for the athlete to reach the ground from maximum height.

Calculate the time taken t_1 by the athlete to reach the maximum height

t_1 = \sqrt{\frac{2h}{g}}

t_1 = \sqrt{\frac{2(1.25)}{9.8}}

t_1 = 0.5s

The athlete takes same time to reach the ground from the maximum height, so t_2 = 0.5s

Calculate the hang time will be

t =t_1+t_2

t = 0.5+0.5

t = 1s

Therefore the hang time of the athlete when he moves a horizontal distance of 3m is 1s.

Similarly, when the athlete runs 6m horizontally, then also there will not be a change in the hang time of the athlete as the hang time is independent of the horizontal distance covered.

4 0
3 years ago
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