A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
rom the original and 2.5 meters lower. How long (in seconds) will it take him to cross between buildings?
1 answer:
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(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
c) Similarly, the third lowest frequency (third harmonic) is given by
where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
b) The frequency of the nth-harmonic for a standing wave in a wire is given by
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
c) Similarly, the third lowest frequency (third harmonic) is given by