Freezing. This stage forms crystal lattice.
Answer:
small car since they weigh less than a bus
Explanation:
Answer:
915.69549 m
306.1968 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration = 3.25 m/s²
g = Acceleration due to gravity = 9.81 m/s²
Height is given by
Total distance the canister has to travel is 230+76.1968 = 306.1968 m
Time to reach the max height
Time taken to reach the ground is
Total time taken would be 3.9413+7.9 = 11.8413 seconds
The rocket is 685.69549+230 = 915.69549 m from the launchpad.
The total distance is 230+76.1968 = 306.1968 m
The particle has a constant horizontal velocity, and a vertical force won't affect the horizontal speed, so it should be fairly easy to find the last part, "the time taken for a 10m horizontal displacement," using a kinematic equation.
X = x + vt + (1/2)at²
10 = 0 + (1.6)t + (1/2)(0)t²
10/1.6 = t
t = 6.25s
So now we have to find the vertical displacement over 6.25 seconds on a particle of a 2.5kg mass with a force of 8N.
Start with Newton's second law.
F = ma
8 = (2.5)a
a = 3.2m/s²
Now, use kinematics again.
Y = y + vt + (1/2)at²
Y = 0 + (0)(6.25) + (1/2)(3.2)(6.25)²
Y = <u>62.5m</u>
Given: Mass m = 0.50 Kg; Force = Weight = mg F = (0.50 Kg)(9.8 m/s²)
F = 4.9 N
Displacement x = 3.0 cm convert to meter x = 0.03 m
Required: Spring constant k = "
Formula: F = kx
k = F/x
k = 4.9 N/0.03 m
k = 163.33 N/m