All categories

3 years ago

use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help

Physics

1 answer:

kati45 [8]3 years ago

3 0

Answer:

L = 3.51

Explanation:

Pendulum equation is T = 2pi $\sqrt{L/9.81}$

T = 1.5 and we are solving for L

1.5=2 $\pi \sqrt{L/9.81}$

square both sides to get 2.25 = 2 $\pi ( L/9.81)$

multiply both sides by 9.81 then divide by 2 and 3.14 as a substitue for pi. The answer should be about 3.51 in length

L = 3.51

If this helps, mark me brainliest pls

You might be interested in

A rocket is fired vertically upwards starting frkm rest. It accelerates at 30m/s for 4secs. At the end of 4secs it runs out of f

HACTEHA [7]

Answer:

t = 16.5 s

Explanation:

First we apply first equation of motion to the accelerated motion of the rocket:

$v_{f1} = v_{i1} + at_{1}$

where,

vf₁ = final speed of rocket during accelerated motion = ?

vi₁ = initial speed of rocket during accelerated motion = 0 m/s

a = acceleration of rocket during accelerated motion = 30 m/s²

t₁ = time taken during accelerated motion = 4 s

Therefore,

$v_{f} = 0\ m/s + (30\ m/s^2)(4\ s)\\\\v_{f} = 120\ m/s$

Now, we analyze the motion rocket when engine turns off. So, the rocket is now in free fall motion. Applying 1st equation of motion:

$v_{f2} = v_{i2} + g t_{2}$

where,

vf₂ = final speed of rocket after engine is off = 0 m/s

vi₂ = initial speed of rocket after engine is off = Vf₁ = 120 m/s

g = acceleration of rocket after engine is off = - 9.8 m/s² (negative sign for upward motion)

t₂ = time taken after engine is off = ?

Therefore,

$0\ m/s = 120\ m/s + (- 9.8\ m/s^2)(t_{2})\\\\t_{2} = \frac{120\ m/s}{9.8\ m/s^2}\\\\t_{2} = 12.25\ s$

So, the time taken from the firing position till the stopping position is:

$t = t_{1} + t_{2}\\\\t = 4 s + 12.5 s$

8 0

3 years ago

Which trends is indirectly proportional to effective nuclear charge

Minchanka [31]

Answer:

Atomic size

Explanation:

In the periodic table , atomic size is indirectly proportional to the effective nuclear charge .the atomic size reduces from left to right across the table. This is because electrons are added to the same shell.

4 0

3 years ago

A ball is batted straight up into the air and reaches a maxium height 65.6 m (a) How long did it take to reach this height? (b)

kondaur [170]

Answer:

a) 3.65 seconds

b) 35.87 m/s

Explanation:

s = Displacement = 65.6 m

u = Initial velocity

v = Final velocity

t = Time taken

a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive and upward is taken as negative)

b) Equation of motion

$v^2-u^2=2as\\\Rightarrow 0^2-u^2=2\times -9.81\times 65.6\\\Rightarrow u=\sqrt{2\times 9.81\times 65.6}\\\Rightarrow u=35.87\ m/s$

Initial pop up velocity is 35.87 m/s

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-35.87}{-9.81}\\\Rightarrow t=3.65\ s$

It took 3.65 seconds to reach this height

6 0

3 years ago

Two coulombs of charge pass through a wire in 5 seconds. Calculate the current in the wire. 1

gogolik [260]

Answer:

0.4A.

Explanation:

Current (A) = Charge (coulomb)/Time (secs)

2 coulombs/5 secs = 0.4A

7 0

3 years ago

It took 1700 J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.

Alenkasestr [34]

The work to stretch a spring from its rest position is

   (1/2) (spring constant) (distance of the stretch)²

   E = 1/2 k x² .

You said it takes 1700 joules to stretch the spring 3 meters from its rest position, so we can write

   1700 joules = 1/2 k (3m)²

1 joule = 1 newton-meter

   1700 N-m = 1/2 k (3m)²

Multiply each side by 2: 3400 N-m = k · 9m²

Divide each side by 9m²    k = 3400 N-m / 9m²

   = (377 and 7/9)   newton per meter

7 0

3 years ago

Read 2 more answers

use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help ​

use the pendulum equation to calcuate the period of a 1.50 pendulum. Remeber that the vaule of "g" is 9.81 m/s² please help