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3 years ago

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How to simply 4 (2x)^3

1 answer:

Kruka [31]3 years ago

3 0

Remember the order of operations. The first step in this problem will be to solve the exponent.

Take (2x)^3. Remember that since there are parentheses around 2x, that means you have to cube 2 and x.

(2x)^3 = 2^3 * x^3 = 8x^3

Now multiply that answer by 4 to finish simplifying.

8x^3 * 4 = 32 x^3

Your answer should be: 32x^3

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How to solve 4(a-2)=3(a+4)

Blababa [14]

Use the distributive property.
4a - 8 = 3a + 12
Arrange the like terms.
4a - 3a = 12 + 8
a = 20
That is the answer. <span>☺️</span>✌️

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3 years ago

Find the height of a cuboid whose volume is 540 cu.cm and base area is 90 sq.cm .

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2 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

2 years ago

Read 2 more answers

yawa3891 [41]

Answer:

Step-by-step explanation:

4 0

2 years ago