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Paraphin [41]
3 years ago
12

!!!!!!!!!!! I will mark as brilliant

Chemistry
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

All matter is made up of tiny particles called <em><u>a</u></em><em><u>t</u></em><em><u>o</u></em><em><u>m</u></em><em><u>s</u></em><em><u>.</u></em> Atoms are made up of three subatomic particles known as <em><u>proton</u></em><em><u>,</u></em><em><u> </u></em><em><u>neutron</u></em><u> </u>and<em><u> </u></em><em><u>electron</u></em><em><u>.</u></em> Protons and neutrons are located in the <em><u>nucleus</u></em><em><u>.</u></em>

The nucleus is dense and takes up very little space within the atom. All protons have a <em><u>positive</u></em><em><u> </u></em>charge and have a mass of about 1 amu. All neutrons have no charge or are <em><u>neutral</u></em> and have a mass of about 1 amu.

Electrons are located in the area known as electron cloud. Electrons orbit around the nucleus and have a <em><u>negative</u></em> charge

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Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
AnnZ [28]

<u>Answer:</u> The limiting reagent is oxygen gas.

<u>Explanation:</u>

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For propane:</u>

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol

  • <u>For oxygen:</u>

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol

The chemical equation for the combustion of propane follows:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = \frac{1}{5}\times 2.34=0.468mol of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

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Answer:

Hint As we know that the concept of mole is mainly to calculate the entities at the microscopic level that is ions, particles, molecules, electrons or atoms etc. It is found that mole is having the symbol mol.

Complete Step by step solution:

- As we are being provided with the information that there is 15 grams of lithium. As we know that the molar mass of lithium is 6.94 g/mol.

- As we know that mole is the amount of substance that has entities as there are atoms exactly in 12 g of carbon isotope. We should note that the number of entities in one mole is important because it is called the Avogadro constant. The numeric value of this constant is 6.022×1023.

- Firstly we will write the given mass as:

156.022×1023

- Now, we can find the number of moles by the formula of moles that is given mass of the substance divided by the molar mass of the substance.

moles=given massmolar mass⟹156.022×10236.94⟹15×6.946.022×1023⟹17.28×10−23moles

- Hence, we can conclude that there are 17.28×1023 moles in 15 grams of lithium.

Note:

- If we want to calculate the number of moles of an individual entity, like say A, that is dissolved in a solution of an entity say B (A+B), then we can do so by using the concept of mole fraction. The formula of mole fraction is given as moles of a substance divided by the total number of moles.

- We should not forget to write the unit after solving the solution. Explanation:

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