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Vaselesa [24]
3 years ago
8

Does a reaction occur when aqueous solutions of chromium(III) bromide and manganese(II) nitrate are combined?

Chemistry
1 answer:
MissTica3 years ago
5 0

Answer:

Yes the reaction occur when aqueous solutions happened

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Tapeworm and Roundworn​
Inessa [10]

Answer:

Tapeworms and roundworms both belong to the same phylum however, their families are different from one another.

Tapeworms are flat, segmented intestinal parasites of the cat and dog and humans sometimes. They are present in the intestines of pets and depend on them, therefore, are parasites. These parasites look like tape which gives it its name.

Roundworms can also infect humans and the most common cases are among children. When not treated immediately, they can cause severe damage to a human host and can even cause blindness. Tapeworms are white in color with a long, segmented body.

5 0
3 years ago
What's the valency of lead in pbO2​
Andru [333]

The valence of lead is 4.

Hence the name of the compound is called Lead (IV) oxide.

<h3>Further explanation</h3>

Given

PbO₂ compound

Required

The valence of Pb

Solution

The oxidation number of element O in the compound = -2, except for OF₂ the oxidation state = + 2 and the peroxides (Na₂O₂, BaO₂) the oxidation state = -1 and superoxide, for example KO₂ = -1/2.

The oxidation state in the uncharged compound = 0,

So The oxidation state of Pb :

Pb + 2.(-2) = 0

Pb - 4 = 0

Pb = +4

8 0
3 years ago
1.The movement of particles from a less crowded area to a more crowded area requires
Harrizon [31]
1. Energy as particles can't move without kinetic (movement) energy 
2. I think it's Diffusion and Active Transport 
7 0
4 years ago
en el átomo la suma entre el número de protones ( número atómico) y el número de neutrones, se denomina ​
Brut [27]

Answer:

nucleo

djesjfsfsp

4 0
3 years ago
A compound has a molecular weight of 146 g/mol. A 0.3250 g sample of the compound contains 0.1605 g of carbon, 0.0220 g of hydro
Sonbull [250]

Answer: The molecular formula is C_6H_{10}S_2

Explanation:

We are given:

Mass of C = 0.1605 g

Mass of H= 0.0220 g

mass of S = 0.1425 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.1605g}{12g/mole}=0.0134moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0220g}{1g/mole}=0.0220moles

Moles of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{0.1425g}{32g/mole}=0.0044moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{0.0134}{0.0044}=3

For H = \frac{0.0220}{0.0044}=5

For S =\frac{0.0044}{0.0044}=1

The ratio of C : H: S=  3: 5: 1

Hence the empirical formula is C_3H_5S

The empirical weight of C_3H_5S = 3(12)+5(1)+1(32)= 73g.

The molecular weight = 146 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{146}{73}=2

The molecular formula will be=2\times C_3H_5S=C_6H_{10}S_2

7 0
3 years ago
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