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Diano4ka-milaya [45]
3 years ago
15

A producer of personal computer mouse pads determines that the number, N, of pads sold is related to the price, X, of a pad by N

=35x-x^2. at what roice is th ecost so high, that no one wants to buy the any mouse pads?
Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

If the cost X is higher or equal than 35, then no one wants to buy the any mouse pads.

Step-by-step explanation:

When N is 0 or lower then it means that no one buys it.

N=35x-x^{2}, if N=0 then

0=35x-x^{2} or

35x=x^{2} dividing each side by x we get:

35=x

This is the cost which nobody will buy the mouse pad anymore.

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1.36 as a fraction help
iogann1982 [59]

Answer: 34/25

Step-by-step explanation:

(136÷4)(100÷4) = 34/25 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction,

7 0
3 years ago
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Solve for y. Answer to the nearest tenth
AysviL [449]

Answer:

y = 11.5

Step-by-step explanation:

Given 2 secants from an external point to the circle.

Then the product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is

6(6 + y) = 5(5 + 16)

36 + 6y = 5 × 21 = 105 ( subtract 36 from both sides )

6y = 69 ( divide both parts by 6 )

y = 11.5

7 0
3 years ago
The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.
finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So,  1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0
3 years ago
According to a 2014 research study of national student engagement in the U.S., the average college student spends 17 hours per w
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 17

For the alternative hypothesis,

µ < 17

This is a left tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 80,

Degrees of freedom, df = n - 1 = 80 - 1 = 79

t = (x - µ)/(s/√n)

Where

x = sample mean = 15.6

µ = population mean = 17

s = samples standard deviation = 4.5

t = (15.6 - 17)/(4.5/√80) = - 2.78

We would determine the p value using the t test calculator. It becomes

p = 0.0034

Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.

The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.

4 0
4 years ago
How do you solve?3(t+4)-2(2t+3)=-4
shepuryov [24]
3t+12-4t-6=-4
-t=-4+6-12
-t=-10
t=10
That's your answer.
8 0
3 years ago
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