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defon
3 years ago
5

A segment has exactly one end point.. True. or. False

Mathematics
1 answer:
insens350 [35]3 years ago
8 0
I think the correct answer is false. A segment do not have only one endpoint. A line segment is part of a line that is bounded by two points and contains every point on the line between the two endpoints. Hope this answers your question.
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Is (2, 6) a solution to this system of equations?<br> y = -x + 8<br> y = 5x - 4<br> yes<br> no
Alexxx [7]

Answer:

Yes

Step-by-step explanation:

To see is (2, 6) is a system, we can plug it into the system to check if it gives us true statements:

6 = -2+8

6 = 6

6 = 5(2)-4

6 = 10-4

6 = 6

Both of the equations are true, therefore (2, 6) is a solution to this system.

6 0
2 years ago
What is the rate of change: y=x+5
const2013 [10]

Answer:

x or 1x.

Step-by-step explanation:

The rate of change is slope.

Slope=m

y=mx+b

y=<u>x</u>+5

x is the same thing as 1x. So...

4 0
2 years ago
&gt;
olga nikolaevna [1]

Answer:5

Step-by-step explanation:>

Which exponential function is represented by the

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o f(x) = 2( 3 )

O f(x) = {(2Y

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6 0
2 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
3 years ago
Plz help plzzzzzzzzz
chubhunter [2.5K]

Answer:

47.13cm

Step-by-step explanation:

2×3.142×7.5cm

6 0
3 years ago
Read 2 more answers
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