All categories

3 years ago

What is the average kinetic energy of 1 mole of a gas that is at 100 degrees Celsius?

1 answer:

3 0

The average kinetic energy of an ideal gas is calculated as

KE_avg = 3/2 kT

where T is the temperature in Kelvin and k=R/N_A; R is the universal gas constant and N_A is the number of moles.

Thus, upon substitution we get

KE_avg = 3/2(8.314/1)(100+273)
KE_avg = 3/2(8.314)(373)
KE_avg = 4651.683

The average kinetic energy of 1 mole of a gas at 100 degree Celsius is 4651.683 J.

You might be interested in

Which of the following can be achieved by using a visible-light spectrophotometer?

gulaghasi [49]

1 and 2 i think this is the answer
thnx u

5 0

3 years ago

The mass number of an atom is obtained by totaling the number of _____ and _____.

son4ous [18]

Mass number is the sum of protons and neutrons inside an atom.

Atomic mass = no. of protons + no. of neutrons

8 0

3 years ago

Read 2 more answers

Due to the lower pressure on top of Mt. Everest, water can

Alla [95]

C. 343K
70 degrees C + 273 = 343

4 0

3 years ago

How many moles of Al would be produced from 20 moles of Al2O3?<br> 2Al2O3<br> -><br> 4A1 + 302

Evgesh-ka [11]

<h3>Answer:</h3>

$\displaystyle 40 \ mol \ Al$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2Al₂O₃ → 4Al + 3O₂

[Given] 20 mol Al₂O₃

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Al₂O₃ → 4 mol Al

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 20 \ mol \ Al_2O_3(\frac{4 \ mol \ Al}{2 \ mol \ Al_2O_3})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 40 \ mol \ Al$

<u>Step 4:Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

Since our final answer already has 1 sig fig, there is no need to round.

4 0

3 years ago

How do I do question number 4?

lisabon 2012 [21]

I hope you understood
hit me up if you have any other questions :>

6 0

3 years ago