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AVprozaik [17]
3 years ago
9

A boy kicks a ball with a force of 40 N. At exactly the same moment, a gust of wind blows in the opposite direction of the kick

with a force of 40 N. What happened to the ball?
A. It began to move with a speed of 80 m/s.

B. It did not move.

C. It moved in the direction that the wind was blowing.

D. It moved in the direction of the kick.
Chemistry
2 answers:
aliya0001 [1]3 years ago
8 0
B, the opposing forces are the same, thus, the ball doesn't move back or forward.
a_sh-v [17]3 years ago
7 0

The answer is B the ball doesn’t move

40n—>  <— 40n it equals out

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The Symbol below is used to represent what component in a circuit?
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Actually, I strongly believe it is a switch.
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10g of a non-volatile and non-dissociating solute is dissolved in 200g of benzene.
ehidna [41]

<u>Answer: </u>The molar mass of solute is 115 g/mol.

<u>Explanation:</u>

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m

OR

\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}} ......(1)

where,

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Boiling point of solution = 81.20^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_b = Boiling point elevation constant = 2.53^oC/m

m_{solute} = Given mass of solute = 10 g

M_{solute} = Molar mass of solute = ? g/mol

w_{solvent} = Mass of solvent = 200 g

Putting values in equation 1, we get:

81.20-80.10=1\times 2.53\times \frac{10\times 1000}{M_{solute}\times 200}\\\\M_{solute}=\frac{1\times 2.53\times 10\times 1000}{1.1\times 200}\\\\M_{solute}=115g/mol

Hence, the molar mass of solute is 115 g/mol.

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(D) Neither I nor II

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