2 years ago

Pls help due in 10 mins

Mathematics

2 answers:

BabaBlast [244]2 years ago

6 0

Answer:

Try inserting the Problem

Step-by-step explanation:

quester [9]2 years ago

5 0

I do not see a problem to help with

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Find the value of both variables.

ella [17]

$\cos(45) = \frac{5 \sqrt{2} }{x} \\ \frac{1}{ \sqrt{2} } = \frac{5 \sqrt{2} }{x} \\ x = 10 \\ \\ \tan(45) = \frac{y}{5 \sqrt{2} } \\ 1 = \frac{y}{5 \sqrt{2} } \\ y = 5 \sqrt{2}$

I hope I helped you ^_^

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2 years ago

Find sec theta if theta is in quadrant 4 and sin theta= -1/5

lara31 [8.8K]

Answer:

$\frac{5}{2\sqrt{6} }$

Step-by-step explanation:

Since Θ is in fourth quadrant then cosΘ > 0, as is secΘ

Given

sinΘ = - $\frac{1}{5}$ , then

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Hence

secΘ = $\frac{1}{\frac{2\sqrt{6} }{5} }$ = $\frac{5}{2\sqrt{6} }$

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Answer yes

Step-by-step explanation:

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