When f(n)=-8 what is the value of n?

Mathematics

1 answer:

Lelu [443]3 years ago

8 0

Answer:

20 the answer is 20 because you plug in 4 for n.

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By what percent has the rhinoceros weight increased

romanna [79]

let's first off convert those mixed fractions to improper fractions, then get their difference.

$\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}~\hfill \stackrel{mixed}{2\frac{1}{10}}\implies \cfrac{2\cdot 10+1}{10}\implies \stackrel{improper}{\cfrac{21}{10}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{21}{10}-\cfrac{3}{2}\implies \stackrel{\textit{using the LCD of 10}}{\cfrac{(1)21-(5)3}{10}}\implies \cfrac{21-15}{10}\implies \cfrac{6}{10}\implies \cfrac{3}{5}$

now, the original amount, 3/2, if that is the 100%, what is 3/5 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2}\\ \frac{3}{2}&100\\\\ \frac{3}{5}&x \end{array}\implies \cfrac{~~\frac{3}{2}~~}{\frac{3}{5}}=\cfrac{100}{x}\implies \cfrac{3}{2}\cdot \cfrac{5}{3}=\cfrac{100}{x}\implies \cfrac{5}{2}=\cfrac{100}{x} \\\\\\ 5x=200\implies x=\cfrac{200}{5}\implies x=40$

4 0

3 years ago

Angela invested $4000 in an account that earns 5% interest yearly (simple interest). She forgets about it for 12 years. What is

harina [27]

Answer:

$6400

Step-by-step explanation:

4000x.05=200× 12=2400+4000=$6400

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3 years ago

Is the square root of 3 rational or irrational

enyata [817]

Answer:

The square root of three is irrational.

Step-by-step explanation:

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3 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$