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ivanzaharov [21]
3 years ago
13

When f(n)=-8 what is the value of n?

Mathematics
1 answer:
Lelu [443]3 years ago
8 0

Answer:

20 the answer is 20 because you plug in 4 for n.

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What is the slope to this line?
Artyom0805 [142]

Answer:

hello :

Hello : let  A(1,0)    B(0,2)  in this line

the slope is :   (YB - YA)/(XB -XA)




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3 years ago
Need help with this one.<br>8 +  I  5x  -  3  I  &gt;  10
grin007 [14]

8 + |5x - 3| > 10

<span>|5x - 3| > 2</span>

<span>|5x| > 5</span>

<span>[x] > 1</span>

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<span>|5x-3| < -2</span>

<span>|5x| < 1</span>

<span>|x| < \frac{1}{5}</span>

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1 > x <  \frac{1}{5}

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3 years ago
Read 2 more answers
Select the correct answer.
mylen [45]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
5.<br> Which picture shows a rotation of the flag?<br> (1)<br> (2)<br> (3)<br> (4)
RUDIKE [14]

Answer:

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Step-by-step explanation:

4 0
3 years ago
For second answer how do you get it plz urgent plz
inna [77]

Step-by-step explanation:

Complete question is attached.

Answer:

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}BCAB=EDAE

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}ED=ABAE∗BC

Let's substitute figures,

ED = \frac{26 * 5}{20}ED=2026∗5

ED = \frac{130}{20} = 6.5ED=20130=6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}ACAB=CDBE

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}BE=ACAB∗CD

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}BE=2520∗18

BE = \frac{360}{25} = 14.4BE=25360=14.4

Therefore, length Of BE is 14.4cm

I JUST SO THAT IN INTERNET:)

4 0
3 years ago
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