The concentration of carbon monoxide at equilibrium is 0.209 M.
<h3>Concentration of each gas</h3>
CO2 = 2 mol/5 L = 0.4
H2 = 1.5 mol/5L = 0.3
<h3>ICE table</h3>
Create ICE table as shown below
CO2(g) + H2(g) ↔ CO(g) + H2O(g)
I 0.4 0.3 0 0
C - x - x x x
E 0.4 - x 0.3 - x x x
Kc = [CO][H₂O] / [CO₂][H₂]
2.5 = (x²)/(0.4 - x)(0.3 - x)
x² = 2.5(0.4 - x)(0.3 - x)
x² = 2.5(0.12 - 0.7x + x²)
x² = 0.3 - 1.75x + 2.5x²
0 = 1.5x² - 1.75x + 0.3
solve the quadratic equation using formula method;
x = 0.209
Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.
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Answer:
Specific heat capacity is measured by determining how much heat energy is needed to raise one gram of a substance one degree Celsius. The specific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie per gram per degree Celsius
Explanation:
Becuse the earth rotates the opisate way on the other side of the equator forgive me if im wrong.
Answer:
The maximum concentration of Pb(NO3)2 is 2.68 M
Explanation:
Step 1: Data given
Volume of the Pb(NO3)2 solution = 400 mL = 0.400 L
Volume of the 0.01 M NaCl solution = 150 mL = 0.150 L
Ksp = 2.00 * 10^-5
Step 2: The equations
NaCl → Na+ + Cl -
PbCl2 → Pb^2+ + 2Cl-
Step 3: Calculate moles
Moles = volume * molarity
Moles NaCl = 0.150 L * 0.01 M
Moles NaCl = 0.0015 moles
Moles Cl- = 0.0015 moles
Step 4: Calculate total volume
Total volume = 400 + 150 = 550 mL
Step 5: Calculate [Cl-]
Molarity = moles / volume
Molarity Cl- = 0.0015 moles / 0.550 L
Molarity = 0.00273 M
Step 6: Calculate Ksp
Ksp = [Pb^2+]*[Cl-]²
2.00 * 10^-5 = [Pb^2+]* 0.00273²
[Pb^2+] = 2.68 M
[Pb^2+] = [Pb(NO3)2] = 2.68 M
The maximum concentration of Pb(NO3)2 is 2.68 M
