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zmey [24]
2 years ago
6

A buffer was prepared by mixing 1.00 mole of ammonia and 1.00 mole of ammonium chloride to form an aqueous solution with a total

volume of 1.00 liter. To 500 mL of this solution was added 30.0 mL of 1.00 M NaOH. What is the pH of this solution?
Chemistry
1 answer:
lidiya [134]2 years ago
3 0

Answer:

Idek sorry

Explanation:

So sorry i think its 1.00

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What is rust classified as
kotykmax [81]

Rust is classified as Metal Oxide!

4 0
3 years ago
Bromine monochloride is synthesized using the reaction:
Sergeu [11.5K]

Answer:

11.72 grams

Explanation:

Let the equilibrium concentration of BrCl be y

Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M

Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M

From the equation of reaction

1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl

Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M

Kp = [BrCl]^2/[Br2][Cl2]

1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)

y^2/0.002356-0.0535y+0.25y^2 = 0.00011

y^2/0.00011 = 0.002356-0.0536y+0.25y^2

9090.9y^2-0.25y^2+0.0536y-0.002356 = 0

9090.65y^2+0.0535y-0.002356 = 0

The value of y must be positive and is obtained using the quadratic formula

y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M

Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams

4 0
3 years ago
Are ionic bonds more powerful or colvant? And why do molecular compounds not have crystal lattice?
grigory [225]

Answer:

Ionic bonds are more powerful than covalant bonds

Explanation:

This is because of their strong lattice structure formed by the attraction between metals and non-merals.

Molecules donot exhibit crystal lattices because of the covslent bonds present in between their molecules

4 0
2 years ago
Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
Anna007 [38]

Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

4 0
2 years ago
Using this balanced equation: 2 NaOH + H2SO4 —> H2O + Na2SO4
pogonyaev

Answer:

266.25g

Explanation:

8 0
3 years ago
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