Is volume and mass size-dependent

What kinds of scientific investigations involve making observations?

rodikova [14]

<span>1. Coherence Theory (Theory of Coherence)

Based on this theory, a knowledge considered to be true if the knowledge kehoren with the knowledge that exists and has been proven to be true. In the study of mathematics this is usually called the deductive nature.

2. Correspondence Theory (Theory of corespondence)

Based on this theory, a knowledge considered to be true if the knowledge of having a relationship with a reality that is true. This theory is based on the empirical fact that knowledge is true if there are facts that support that is true knowledge. Thus the truth here is based on inductive inference.

3. Pragmatic Theory (Theory of Pragmatism)

According to this theory, knowledge is said to be true if the knowledge is seen practically completely or have properties that true practicality. Followers of this theory argue that knowledge is true if it has keguanaan practical<span>.</span></span>

5 0

3 years ago

A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol

Marat540 [252]

Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

1 gallon = 3.78541 L

4. 50 gallon = 3.785 L x 4.50

So,

initial volume V1 = 17.03 L

final Volume V2 = ?

initial Temperature T1 = 80° F

convert Temperature to Kelvin

T1 = ( 80° F -32) / 1.8 +273

T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

V2 = 17.03 L x 373 K / 299.7 K

V2 = 21. 19 L

So the final volume of Methane gas = 21.19 L

Or for Volume in gallons

1 L = 0.26

21.19 x 0.264 = 5.6 gallons

7 0

3 years ago

What is the partial pressure of radon if the total pressure is 780 torr and the

Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure = 780torr

Partial pressure of water vapor = 1.0atm

Unknown:

Partial pressure of radon = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

P $_{t}$ = P $_{1}$ + P $_{2}$ + P $_{n}$

Since the total pressure is 780torr, convert this to atm;

760torr = 1 atm

780torr = $\frac{780}{760}$ atm = 1.03atm

For this problem;

Total pressure = Partial pressure of radon + Partial pressure of water vapor

1.03 = Partial pressure of radon + 1.0

Partial pressure of radon = 1.03 - 1.00 = 0.03atm

6 0

4 years ago

Obtain the valence shell configuration of Al and S from their positions in the periodic table.

lutik1710 [3]

Answer:

Al: 3

S: 6

Explanation:

Al is in Group III. This means that it has 3 valence electrons.

S is in Group VI. This means that it has 6 valence electrons.

I hope this helps :)

3 0

3 years ago

The elementary reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) proceeds at a certain temperature until the partial pressu

daser333 [38]

Answer:

6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature.

Explanation:

2H₂O(g) ⇄ 2H₂(g) + O₂(g)

Partial pressure of H₂O = 0.0500 atm

Partial pressure of H₂ = 0.00150 atm

Partial pressure of O₂ = 0.00150 atm

The expression of Kp for the given chemical equation is:

$K_p = \frac{[H_2]^2[O_2]}{H_2O}$

$= \frac{(0.00150^2)(0.00150)}{(0.0500)} \\= 6.75 * 10^-^8$

6.75 × 10⁻⁸is the value of the equilibrium constant at this temperature

7 0

4 years ago