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Sphinxa [80]
2 years ago
13

HELP!!!!!!!!!!! WILL GIVE EXTRA POINTS Using the five major types of chemical reactions listed below:

Chemistry
1 answer:
scoray [572]2 years ago
4 0
Is it multiple choice or anwser or each question
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a natrual distsater caused a population of 4,695 organisms to migrate to a new habitat. a few generations after the disaster it
Scilla [17]

Answer:

49.54%

Explanation:

Given parameters:

Number of organisms in original habitat = 4695

Number of organism in new habitat = 2326

Solution:

To find the percentage of the organisms in the new habitat that has migrated to the new habitat, we use the expression below:

% of the population in the new habitat =  x 100

% of the population in the new habitat =  x 100 = 49.54%

7 0
2 years ago
What are some visible signs of an acid-base reaction?
marta [7]
I think one of the signs is <span>water and  salt are formed 

</span>
6 0
3 years ago
Calculate the osmotic pressure of a solution containing 24.6g of glycerin in 250ml of solution at 298K
gavmur [86]
The formula to calculate osmotic pressure is 
Osmotic Pressure = M R T
M = Molarity
R = Ideal Gas Constant
T = Temperature in Kelvin

So, 
24.6/.2254kg=109.139g /kg  >>>>> Molarity
109.139 x mols/92 g = 1.186 mols kg^-1
1.186 x 0.08134 x 298 K = 28.755 atm
<span>1.06852 x 0.08134 x 298K= 26.5 atm

The answer is 26.5</span>
6 0
3 years ago
Periodic table of elements
Sidana [21]

Vertical Column is a group

Horizontal is Period

Aliki earth metals is a group

Lithium- Neon is both

Based on electrons are both

Number of electron shells is both

5 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
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