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andrew11 [14]
3 years ago
15

At a competition with 6 runners, 2 medals are awarded for first and second

Mathematics
1 answer:
insens350 [35]3 years ago
3 0

Answer:

30 ways

Step-by-step explanation:

The first medal can be awarded in 6 different ways since any of the runners could have it. Once the first medal is awarded, the second medal can only be given to any of the 5 runners available.

So there are 6x5=30 different ways to award the medals

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Write the three numbers less then 40 that have 2 and 5 as factors
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No. which have factors 2 & 5 have 2 & 5 as their prime factor
therefore, No. are :
2*5 = 10
2*5*2 = 20
2*5*3 = 30
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Help ASAP Please check to see if I have the last part correct. Thanks
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Write repeating decimal 0.027272727 ... as a fraction. <br><br> Reduce the fraction completely.
umka2103 [35]

Answer:

3/110

Step-by-step explanation:

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2 years ago
Which number had a 3 with a value that is 100 times greater than the value of the 3 in 20.342?
goblinko [34]
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4 0
2 years ago
An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
Rzqust [24]

Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0
2 years ago
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