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andrew11 [14]
3 years ago
15

At a competition with 6 runners, 2 medals are awarded for first and second

Mathematics
1 answer:
insens350 [35]3 years ago
3 0

Answer:

30 ways

Step-by-step explanation:

The first medal can be awarded in 6 different ways since any of the runners could have it. Once the first medal is awarded, the second medal can only be given to any of the 5 runners available.

So there are 6x5=30 different ways to award the medals

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Which equation has the same solution as 10x-x+5=4110 x − x + 5 = 41?
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3 years ago
Kathy is paid $7.50 per hour for babysitting. If she babysits for 5 hours on Friday night, write an equation to represent how mu
nikdorinn [45]

Answer:

$37.5

Step-by-step explanation:

$7.50=in one hr

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since you can cross each other

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4 0
2 years ago
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Imagine a couple who is ready to start a family. They plan to have exactly four children. Assuming no multiple births (twins, tr
Lostsunrise [7]

Answer:

4 different ways

Step-by-step explanation:

Total number of children = 4

Distribution of the 4 children :

Number of boys = 3 ; Number of girls = 1

Boy = B ; Girl = G

Possible combinations :

BBBG ; GBBB ; BBGB ; BGBB

From the pascal triangle number of e; number of outcomes = 2

Having exactly 3 boys and 1 girl

Hence, of any of the 4 four total children, 3 must be boys and 1 girl ;

7 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
Identify the equation of the parabola in vertex form if a = 1 and the vertex is (4, 6).
Y_Kistochka [10]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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