All categories

4 years ago

PLEASE HELP IM DUMB!!!

Physics

1 answer:

Semenov [28]4 years ago

4 0

Answer:

I believe its: A wave with a shorter wavelength has higher frequency

You might be interested in

a 2.80 kg mass is dropped from a height of 4.50 m. find its potential energy(PE) when it is 3.00 m above the ground.PLEASE HELP

Dennis_Churaev [7]

Answer:

82.3 J

Explanation:

PE = mgh

PE = (2.80 kg) (9.8 m/s²) (3.00 m)

PE = 82.3 J

5 0

4 years ago

What does Neil Degrasse Tyson mean when he says "Wolves domesticated humans" 15000 years ago?

Aliun [14]

Answer:

Explanation:

fufuu6u

8 0

3 years ago

The chart show the masses and velocities of two colliding objects that stick together after a collision.

finlep [7]

Answer:

1,500 kg.m/s

Explanation:

First, arrange the information in a table:

Object Mass (kg) Velocity (m/s)

A 200 15

B 150 - 10

After the collision, the two objects are stick together, thus you talk aobut one object and one momentum.

According to the law of convervation of momentum, the momentum after the collision is equal to the momentum before the collision.

Momentum before the collision, P₁:

$P_1=m_{A,1}\times v_{A,1}+m_{B,1}\times v_{B,1}$

$P_1=200kg\times 15m/s+150kg\times (-10m/s)\\\\ P_1=3000kg.m/s-1500kg.m/s=1500kg.m/s$

Momentum after the collision:

As stated, it es equal to the momentum before the collision: 1,500 kg . m/s

6 0

4 years ago

A bus hits a bug and the bug splatters on the windshield, which force is greater?

grandymaker [24]

The forces acting on a body and the type of motion that results are given by Newton's three Laws of motion

The force of the bus is the same as reactive force of the bug

Reason:

According to Newton's third Law of motion, given that the bug collides

with the bus, the force with which the bus hits the bug is equal to the

reactive force of the bug on the on the bus

According to Newton's second Law of motion, force is equal to the rate of

change of the momentum produced

The impulse of the force of the bus on the bug is given as follows;

F·Δt = m·(v₂ - v₁)

Given that the force of the bus is large, the change in momentum, m·(v₂ - v₁),

is also large such that the parts of the bug are split by the rapid change in

velocity, and the bug splatters on the windshield, and is then carried along

on the trip,

The equally large reactive force of the bug, is such that the bug splatters

due its magnitude

Therefore, the correct response is that the forces are the same

Lean more here:

brainly.com/question/21279060

8 0

2 years ago

H) Find the inverse Laplace transforms of the equation. When the X(s) =1 /(s²+9s+20)

Anastasy [175]

Answer:

e^-4t e^-5t

Explanation:

solving s²+9s+20 quadratically we have (s+4)(s+5)

x(s) can be written as x(s) =(1/s+4)(1/s+5)

if we take the laplace inversve

L-¹ (s)=L-1(1/s+4) L-1(1/s+5)

we have e^-4t e^-5t

7 0

1 year ago