Answer:
10m/s
Explanation:
Using the law of conservation of momentums
M1u1+m2u2 = (m1+m2)v
Substitute.
4000(10)+1500(10) = (4000+1500)v
40,000+15,000 = 5,500v
55000 = 5500v
v = 55000/5500
v= 10m/s
Hence the velocity of the truck after Collision is 10m/s
The friction force does the greatest magnitude of work on the crate
Consider all four forces. The normal force does no work at all, since there is no motion in the direction of that force, perpendicular to the ramp. The force of gravity is smaller than the force of friction, since you still need to push the crate to get constant velocity. The force of you pushing is also smaller than the force of friction, since you are moving down a ramp, and are therefore assisted by gravity. Therefore the force doing greatest magnitude of work is the force of friction. Note that, even though the frictional work is negative, it still has the greatest magnitude
Learn more about friction force here:
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Answer:
(you can use my exact words) The length and thickness would make it so that the electrons move differently than they would a shorter and thinner wire because with the wire being longer the electrons would have a longer trip and with the wire being thicker the electrons would be more spread out and move be able to move more freely
Responda:
400 g
Explicação:
Dado o seguinte:
Deixe Mass (m1) = m em t1 = 45 ° C
Massa (m2) = 200g em t2 = 15 ° C
Equilíbrio térmico (T) = 35 ° C
Usando a relação:
m1 * C * ΔT = m2 * C * ΔT
Onde m1 e m2 são as massas; C = capacidade de calor específico da água e ΔT é a mudança de temperatura
m1 * ΔT = m2 * ΔT
m * (45 ° C - 35 ° C) = 200 * (35 ° C - 15 ° C)
10 * m = 200 * 20
10 * m = 4000
m = 4000/10
m = 400g
Answer:
The induced emf in the coil at the t = 5s is 6.363 mV
Explanation:
Given;
number of turns = 75
diameter of the coil = 6 cm
magnetic field strength = 1 T
new magnetic field strength = 1.30 T at t = 10.0 s


Between 0 to 5 s, Induced emf is given as;

Between 5 to 10 s, Induced emf is given as;

Since the field increased at a uniform rate until it reaches 1.30 T at t = 10.0 s, the induced emf will also increase in uniform rate. And equal time interval will generate same increase in field strength.
B₅ -1 = 1.3 - B₅
2B₅ = 2.3
B₅ = 1.15 T
Thus, magnetic field at t = 5 is 1.15 T

Therefore, the induced emf in the coil at the t = 5s is 6.363 mV