Answer:
the magnitude of first force = 3 × 5= 15 N
ANd, the magnitude of second force = 5 × 5 = 25 N
Explanation:
The computation of the magnitude of the each force is shown below:
Provided that
Ratio of forces = 3: 5
Let us assume the common factor is x
Now
first force = 3x
And, the second force = 5x
Resultant force = 35 N
The Angle between the forces = 60 degrees
Based on the above information
Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos
35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]
35 =√ 9x² + 25x² + 15x² (cos 60° = 0.5)
35 = √49 x²
x = 5
So, the magnitude of first force = 3 × 5= 15 N
ANd, the magnitude of second force = 5 × 5 = 25 N
Try to have a calm morning before camp. A good night’s sleep and a good breakfast. Make sure to be cautious, follow all the rules for certain areas ( some maybe restricted ). Take lots of photos doing wacky stuff! Learn but have fun learning
Answer:
All
Explanation:
I'm not sure what you meant but Newton's third law which basically states that every action has an equal and opposite reaction applies to <em>all</em> objects. So I think the answer is all.
The most useful meteorological measurement for forecasting freezing precipitation is b. radiosonde soundings
<h3>
Radiosonde </h3>
At high altitudes, radiosondes are battery-powered telemetry sensor bundles that detect altitude, pressure, temperature, relative humidity, wind (both speed and direction), and cosmic ray measurements. They are commonly taken into the atmosphere by weather balloons.
Rawindsonde is an acronym for radar wind sonde, a type of radiosonde that tracks its position as it rises through the sky to provide wind speed and direction. Another type of radiosonde is one that falls to the ground after being released from an aircraft, as opposed to being carried by weather balloons. The term "dropsondes" is used to describe this group of radiosondes. The majority of operational atmospheric data assimilation methods depend heavily on radiosondes.
Learn more about radiosonde here:
brainly.com/question/10510287
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Answer:
a)
0.245 m/s
b)
0.904 m
Explanation:
a)
= speed of duck ahead of wave
= speed of surface wave = 0.32 m/s
T = time for paddling = 1.6 s
d = spacing between the waves = 0.12 m
speed of duck ahead of wave is given as
=
- 
= 0.32 - 
= 0.245 m/s
b)
= speed of wave behind the duck
speed of wave behind the duck is given as
=
+ 
= 0.32 + 0.245
= 0.565 m/s
D = spacing between the crests
spacing between the crests is given as
D =
T
D = (0.565) (1.6)
D = 0.904 m