Question

8x + 1 = -8 - X Answer? Please

Answer 1

Answer:

$x = -1$

Step-by-step explanation:

-Solve for $x$ :

$8x + 1 = -8 - x$

-Add both side by $x$ :

$8x + 1 + x = -8 - x + x$

$9x + 1 = -8$

-Subtract both sides by $1$ :

$9x + 1 - 1 = -8 - 1$

$9x = -9$

-Divide both sides by $9$ :

$\frac{9x}{9} = \frac{-9}{9}$

$x = -1$

So, the value of $x$ is $-1$.

Answer 2

Answer:

$\boxed{\sf x = - 1}$

Step-by-step explanation:

$\sf Solve \: for \: x: \\ \sf \implies 8x + 1 = - 8 - x \\ \\ \sf Add \: x \: to \: both \: sides: \\ \sf \implies 8x + x + 1 = - 8 + (x - x ) \\ \\ \sf x - x = 0 : \\ \sf \implies 8x +x + 1 = - 8 \\ \\ \sf 8x + x = 9x : \\ \sf \implies 9x + 1 = - 8 \\ \\ \sf Subtract \: 1 \: from \: both \: sides: \\ \sf \implies 9x + (1 - 1 )= - 8 - 1 \\ \\ \sf 1 - 1 = 0 : \\ \sf \implies 9x = - 8 - 1 \\ \\ \sf - 8 - 1 : \\ \sf \implies 9x = - 9 \\ \\ \sf Divide \: both \: sides \: of \: 9 x = 9 \: by \: 9: \\ \sf \implies \frac{9x}{9} = - \frac{9}{9} \\ \\ \sf \frac{9}{9} = 1 : \\ \sf \implies x = - 1$